Overload resolution
In order to compile a function call, the compiler must first perform name lookup, which, for functions, may involve argument-dependent lookup, and for function templates may be followed by template argument deduction.
If the name refers to more than one entity, it is said to be overloaded, and the compiler must determine which overload to call. In simple terms, the overload whose parameters match the arguments most closely is the one that is called.
In detail, overload resolution proceeds through the following steps:
- Building the set of candidate functions.
- Trimming the set to only viable functions.
- Analyzing the set to determine the single best viable function (this may involve ranking of implicit conversion sequences)
void f(long); void f(float); f(0L); // calls f(long) f(0); // error: ambiguous overload
Besides function calls, overloaded function names may appear in several additional contexts, where different rules apply: see Address of an overloaded function.
If a function cannot be selected by overload resolution, it cannot be used. (e.g. it is a templated entity with a failed constraint)
[edit] Candidate functions
Before overload resolution begins, the functions selected by name lookup and template argument deduction are combined to form the set of candidate functions. The exact details depend on the context in which overload resolution takes place:
[edit] Call to a named function
If E
in a function call expression E(args)
names a set of overloaded functions and/or function templates (but not callable objects), the following rules are followed:
- If the expression
E
has the formPA->B
orA.B
(where A has class type cv T), thenB
is looked up as a member function ofT
. The function declarations found by that lookup are the candidate functions. The argument list for the purpose of overload resolution has the implied object argument of type cv T. - If the expression
E
is a primary expression, the name is looked up following normal rules for function calls (which may involve ADL). The function declarations found by this lookup are (due to the way lookup works) either:
- a) all non-member functions (in which case the argument list for the purpose of overload resolution is exactly the argument list used in the function call expression)
- b) all member functions of some class
T
, in which case, if this is in scope and is a pointer toT
or to a derived class ofT
,*this
is used as the implied object argument. Otherwise (ifthis
is not in scope or does not point toT
), a fake object of typeT
is used as the implied object argument, and if overload resolution subsequently selects a non-static member function, the program is ill-formed.
[edit] Call to a class object
If E
in a function call expression E(args)
has class type cv T
, then
- The function-call operators of T are obtained by ordinary lookup of the name operator() in the context of the expression
(E).operator()
, and every declaration found is added to the set of candidate functions. - For each non-explicit user-defined conversion function in
T
or in a base ofT
(unless hidden), whose cv-qualifiers are the same or greater thanT
's cv-qualifiers, and where the conversion function converts to:
- pointer-to-function
- reference-to-pointer-to-function
- reference-to-function
- then a surrogate call function with a unique name whose first parameter is the result of the conversion, the remaining parameters are the parameter-list accepted by the result of the conversion, and the return type is the return type of the result of the conversion, is added to the set of candidate functions. If this surrogate function is selected by the subsequent overload resolution, then the user-defined conversion function will be called and then the result of the conversion will be called.
In any case, the argument list for the purpose of overload resolution is the argument list of the function call expression preceded by the implied object argument E
(when matching against the surrogate function, the user-defined conversion will automatically convert the implied object argument to the first argument of the surrogate function).
int f1(int); int f2(float); struct A { using fp1 = int(*)(int); operator fp1() { return f1; } // conversion function to pointer to function using fp2 = int(*)(float); operator fp2() { return f2; } // conversion function to pointer to function } a; int i = a(1); // calls f1 via pointer returned from conversion function
[edit] Call to an overloaded operator
If at least one of the arguments to an operator in an expression has a class type or an enumeration type, both builtin operators and user-defined operator overloads participate in overload resolution, with the set of candidate functions selected as follows:
For a unary operator @
whose argument has type T1
(after removing cv-qualifications), or binary operator @
whose left operand has type T1
and right operand of type T2
(after removing cv-qualifications), the following sets of candidate functions are prepared:
T1
is a complete class or a class currently being defined, the set of member candidates is the result of qualified name lookup of T1::operator@
. In all other cases, the set of member candidates is empty. operator@
in the context of the expression (which may involve ADL), except that member function declarations are ignored and do not prevent the lookup from continuing into the next enclosing scope. If both operands of a binary operator or the only operand of a unary operator has enumeration type, the only functions from the lookup set that become non-member candidates are the ones whose parameter has that enumeration type (or reference to that enumeration type)
4) rewritten candidates:
In all cases, rewritten candidates are not considered in the context of the rewritten expression. For all other operators, the rewritten candidate set is empty. |
(since C++20) |
The set of candidate functions to be submitted for overload resolution is a union of the sets above. The argument list for the purpose of overload resolution consists of the operands of the operator except for operator->
, where the second operand is not an argument for the function call (see member access operator).
struct A { operator int(); // user-defined conversion }; A operator+(const A&, const A&); // non-member user-defined operator void m() { A a, b; a + b; // member-candidates: none // non-member candidates: operator+(a, b) // built-in candidates: int(a) + int(b) // overload resolution chooses operator+(a, b) }
If the overload resolution selects a built-in candidate, the user-defined conversion sequence from an operand of class type is not allowed to have a second standard conversion sequence: the user-defined conversion function must give the expected operand type directly:
struct Y { operator int*(); }; // Y is convertible to int* int *a = Y() + 100.0; // error: no operator+ between pointer and double
For operator,, the unary operator&, and operator->, if there are no viable functions (see below) in the set of candidate functions, then the operator is reinterpreted as a built-in.
If a rewritten operator<=> candidate is selected by overload resolution for an operator If a rewritten operator== candidate is selected by overload resolution for an operator Overload resolution in this case has a final tiebreaker preferring non-rewritten candidates to rewritten candidates, and preferring non-synthesized rewritten candidates to synthesized rewritten candidates. This lookup with the reversed arguments order makes it possible to write just operator<=>(std::string, const char*) and operator==(std::string, const char*) to generate all comparisons between std::string and const char*, both ways. See default comparisons for more detail. |
(since C++20) |
[edit] Initialization by constructor
When an object of class type is direct-initialized or default-initialized outside a copy-initialization context, the candidate functions are all constructors of the class being initialized. The argument list is the expression list of the initializer.
When an object of class type is copy-initialized from an object of the same or derived class type, or default-initialized in a copy-initialization context, the candidate functions are all converting constructors of the class being initialized. The argument list is the expression of the initializer.
[edit] Copy-initialization by conversion
If copy-initialization of an object of class type requires that a user-defined conversion is called to convert the initializer expression of type cv S
to the type cv T
of the object being initialized, the following functions are candidate functions:
- all converting constructors of
T
- the non-explicit conversion functions from
S
and its base classes (unless hidden) toT
or class derived fromT
or a reference to such. If this copy-initialization is part of the direct-initialization sequence of cvT
(initializing a reference to be bound to the first parameter of a constructor that takes a reference to cvT
), then explicit conversion functions are also considered.
Either way, the argument list for the purpose of overload resolution consists of a single argument which is the initializer expression, which will be compared against the first argument of the constructor or against the implicit object argument of the conversion function.
[edit] Non-class initialization by conversion
When initialization of an object of non-class type cv1 T
requires a user-defined conversion function to convert from an initializer expression of class type cv S
, the following functions are candidates:
- the non-explicit user-defined conversion functions of
S
and its base classes (unless hidden) that produce typeT
or a type convertible toT
by a standard conversion sequence, or a reference to such type. cv qualifiers on the returned type are ignored for the purpose of selecting candidate functions. - if this is direct-initialization, the explicit user-defined conversion functions of
S
and its base classes (unless hidden) that produce typeT
or a type convertible toT
by a qualification conversion, or a reference to such type, are also considered.
Either way, the argument list for the purpose of overload resolution consists of a single argument which is the initializer expression, which will be compared against the implicit object argument of the conversion function.
[edit] Reference initialization by conversion
During reference initialization, where the reference to cv1 T
is bound to the lvalue or rvalue result of a conversion from the initializer expression from the class type cv2 S
, the following functions are selected for the candidate set:
- the non-explicit user-defined conversion functions of
S
and its base classes (unless hidden) to the type
- (when initializing lvalue reference or rvalue reference to function) lvalue reference to cv2
T2
- (when initializing rvalue reference or lvalue reference to function) cv2
T2
or rvalue reference to cv2T2
- (when initializing lvalue reference or rvalue reference to function) lvalue reference to cv2
- where cv2 T2 is reference-compatible with cv1 T
- for direct initialization, the explicit user-defined conversion functions are also considered if T2 is the same type as T or can be converted to type T with a qualification conversion.
Either way, the argument list for the purpose of overload resolution consists of a single argument which is the initializer expression, which will be compared against the implicit object argument of the conversion function.
[edit] List-initialization
When an object of non-aggregate class type T
is list-initialized, two-phase overload resolution takes place.
- at phase 1, the candidate functions are all initializer-list constructors of
T
and the argument list for the purpose of overload resolution consists of a single initializer list argument - if overload resolution fails at phase 1, phase 2 is entered, where the candidate functions are all constructors of
T
and the argument list for the purpose of overload resolution consists of the individual elements of the initializer list.
If the initializer list is empty and T
has a default constructor, phase 1 is skipped.
In copy-list-initialization, if phase 2 selects an explicit constructor, the initialization is ill-formed (as opposed to all over copy-initializations where explicit constructors are not even considered).
[edit] Additional rules for function template candidates
If name lookup produces a function template, template argument deduction and checking of any explicit template arguments are performed to find the template argument values (if any) that can be used in this case:
- if both succeeds, the template arguments are used to synthesize declarations of the corresponding function template specializations, which are added to the candidate set, and such specializations are treated just like non-template functions except where specified otherwise in the tie-breaker rules below;
- if argument deduction fails or the synthesized function template specialization would be ill-formed, no such function is added to the candidate set (see SFINAE).
If a name refers to one or more function templates and also to a set of overloaded non-template functions, those functions and the specializations generated from the templates are all candidates.
See function template overloading for further detail.
If a constructor template or conversion function template has a conditional explicit specifier which happens to be value-dependent, after deduction, if the context requires a candidate that is not explicit and the generated specialization is explicit, it is removed from the candidate set. |
(since C++20) |
[edit] Additional rules for constructor candidates
Defaulted move constructor and move assignment that are defined as deleted are never included in the list of candidate functions. |
(since C++11) |
Inherited copy and move constructors are not included in the list of candidate functions when constructing a derived class object.
[edit] Additional rules for member function candidates
If any candidate function is a member function (static or non-static) that does not have an explicit object parameter (since C++23), but not a constructor, it is treated as if it has an extra parameter (implicit object parameter) which represents the object for which they are called and appears before the first of the actual parameters.
Similarly, the object on which a member function is being called is prepended to the argument list as the implied object argument.
For member functions of class X
, the type of the implicit object parameter is affected by cv-qualifications and ref-qualifications of the member function as described in member functions.
The user-defined conversion functions are considered to be members of the implied object argument for the purpose of determining the type of the implicit object parameter.
The member functions introduced by a using-declaration into a derived class are considered to be members of the derived class for the purpose of defining the type of the implicit object parameter.
For the static member functions, the implicit object parameter is considered to match any object: its type is not examined and no conversion sequence is attempted for it.
For the rest of overload resolution, the implied object argument is indistinguishable from other arguments, but the following special rules apply to the implicit object parameter:
struct B { void f(int); }; struct A { operator B&(); }; A a; a.B::f(1); // Error: user-defined conversions cannot be applied // to the implicit object parameter static_cast<B&>(a).f(1); // OK
[edit] Viable functions
Given the set of candidate functions, constructed as described above, the next step of overload resolution is examining arguments and parameters to reduce the set to the set of viable functions
To be included in the set of viable functions, the candidate function must satisfy the following:
M
arguments, the candidate function that has exactly M
parameters is viableM
parameters, but has an ellipsis parameter, it is viable.M
parameters and the M+1
'st parameter and all parameters that follow have default arguments, it is viable. For the rest of overload resolution, the parameter list is truncated at M.
4) If the function has an associated constraint, it must be satisfied
|
(since C++20) |
User-defined conversions (both converting constructors and user-defined conversion functions) are prohibited from taking part in implicit conversion sequence where it would make it possible to apply more than one user-defined conversion. Specifically, they are not considered if the target of the conversion is the first parameter of a constructor or the implicit object parameter of a user-defined conversion function, and that constructor/user-defined conversion is a candidate for
- copy-initialization of a class by user-defined conversion,
- initialization of a non-class type by a conversion function,
- initialization by conversion function for direct reference binding,
- initialization by constructor during the second (direct-initialization) step of class copy-initialization,
struct A { A(int); }; struct B { B(A); }; B b{{0}}; // list-initialization of B // candidates: B(const B&), B(B&&), B(A) // {0} -> B&& not viable: would have to call B(A) // {0} -> const B&: not viable: would have to bind to rvalue, would have to call B(A) // {0} -> A viable. Calls A(int): user-defined conversion to A is not banned |
(since C++11) |
[edit] Best viable function
For each pair of viable function F1
and F2
, the implicit conversion sequences from the i
-th argument to i
-th parameter are ranked to determine which one is better (except the first argument, the implicit object argument for static member functions has no effect on the ranking)
F1
is determined to be a better function than F2
if implicit conversions for all arguments of F1 are not worse than the implicit conversions for all arguments of F2, and
3) or, if not that, (only in context of initialization by conversion function for direct reference binding of a reference to function type), the return type of F1 is the same kind of reference (lvalue or rvalue) as the reference being initialized, and the return type of F2 is not
|
(since C++11) |
6) or, if not that, F1 and F2 are non-template functions with the same parameter-type-lists, and F1 is more constrained than F2 according to the partial ordering of constraints
|
(since C++20) |
7) or, if not that, F1 is a constructor for a class D, F2 is a constructor for a base class B of D, and for all arguments the corresponding parameters of F1 and F2 have the same type:
struct A { A(int = 0); }; struct B: A { using A::A; B(); }; B b; // OK, B::B() |
(since C++11) |
8) or, if not that, F2 is a rewritten candidate and F1 is not,
9) or, if not that, F1 and F2 are both rewritten candidates, and F2 is a synthesized rewritten candidate with reversed order of parameters and F1 is not,
|
(since C++20) |
10) or, if not that, F1 is generated from a user-defined deduction-guide and F2 is not
11) or, if not that, F1 is the copy deduction candidate and F2 is not
12) or, if not that, F1 is generated from a non-template constructor and F2 is generated from a constructor template:
template<class T> struct A { using value_type = T; A(value_type); // #1 A(const A&); // #2 A(T, T, int); // #3 template<class U> A(int, T, U); // #4 }; // #5 is A(A), the copy deduction candidate A x (1, 2, 3); // uses #3, generated from a non-template constructor template<class T> A(T) -> A<T>; // #6, less specialized than #5 A a (42); // uses #6 to deduce A<int> and #1 to initialize A b = a; // uses #5 to deduce A<int> and #2 to initialize template<class T> A(A<T>) -> A<A<T>>; // #7, as specialized as #5 A b2 = a; // uses #7 to deduce A<A<int>> and #1 to initialize |
(since C++17) |
These pair-wise comparisons are applied to all viable functions. If exactly one viable function is better than all others, overload resolution succeeds and this function is called. Otherwise, compilation fails.
void Fcn(const int*, short); // overload #1 void Fcn(int*, int); // overload #2 int i; short s = 0; void f() { Fcn(&i, 1L); // 1st argument: &i -> int* is better than &i -> const int* // 2nd argument: 1L -> short and 1L -> int are equivalent // calls Fcn(int*, int) Fcn(&i, 'c'); // 1st argument: &i -> int* is better than &i -> const int* // 2nd argument: 'c' -> int is better than 'c' -> short // calls Fcn(int*, int) Fcn(&i, s); // 1st argument: &i -> int* is better than &i -> const int* // 2nd argument: s -> short is better than s -> int // no winner, compilation error }
If the best viable function resolves to a function for which multiple declarations were found, and if any two of these declarations inhabit different scopes and specify a default argument that made the function viable, the program is ill-formed.
namespace A { extern "C" void f(int = 5); } namespace B { extern "C" void f(int = 5); } using A::f; using B::f; void use() { f(3); // OK, default argument was not used for viability f(); // error: found default argument twice }
[edit] Ranking of implicit conversion sequences
The argument-parameter implicit conversion sequences considered by overload resolution correspond to implicit conversions used in copy initialization (for non-reference parameters), except that when considering conversion to the implicit object parameter or to the left-hand side of assignment operator, conversions that create temporary objects are not considered.
Each type of standard conversion sequence is assigned one of three ranks:
The rank of the standard conversion sequence is the worst of the ranks of the standard conversions it holds (there may be up to three conversions)
Binding of a reference parameter directly to the argument expression is either Identity or a derived-to-base Conversion:
struct Base {}; struct Derived : Base {} d; int f(Base&); // overload #1 int f(Derived&); // overload #2 int i = f(d); // d -> Derived& has rank Exact Match // d -> Base& has rank Conversion // calls f(Derived&)
Since ranking of conversion sequences operates with types and value categories only, a bit field can bind to a reference argument for the purpose of ranking, but if that function gets selected, it will be ill-formed.
S1
is better than a standard conversion sequence S2
ifS1
is a subsequence of S2
, excluding lvalue transformations. The identity conversion sequence is considered a subsequence of any other conversionS1
is better than the rank of S2
S1
and S2
are binding to a reference parameter to something other than the implicit object parameter of a ref-qualified member function, and S1
binds an rvalue reference to an rvalue while S2
binds an lvalue reference to an rvalue
int i; int f1(); int g(const int&); // overload #1 int g(const int&&); // overload #2 int j = g(i); // lvalue int -> const int& is the only valid conversion int k = g(f1()); // rvalue int -> const int&& better than rvalue int -> const int&
S1
and S2
are binding to a reference parameter and S1
binds an lvalue reference to function while S2
binds an rvalue reference to function.
int f(void(&)()); // overload #1 int f(void(&&)()); // overload #2 void g(); int i1 = f(g); // calls #1
S1
and S2
are binding to a reference parameters only different in top-level cv-qualification, and S1
's type is less cv-qualified than S2
's.
int f(const int &); // overload #1 int f(int &); // overload #2 (both references) int g(const int &); // overload #1 int g(int); // overload #2 int i; int j = f(i); // lvalue i -> int& is better than lvalue int -> const int& // calls f(int&) int k = g(i); // lvalue i -> const int& ranks Exact Match // lvalue i -> rvalue int ranks Exact Match // ambiguous overload: compilation error
the cv-qualification of the result of |
(until C++20) |
the result of |
(since C++20) |
int f(const int*); int f(int*); int i; int j = f(&i); // &i -> int* is better than &i -> const int*, calls f(int*)
U1
is better than a user-defined conversion sequence U2
if they call the same constructor/user-defined conversion function or initialize the same class with aggregate-initialization, and in either case the second standard conversion sequence in U1
is better than the second standard conversion sequence in U2
struct A { operator short(); // user-defined conversion function } a; int f(int); // overload #1 int f(float); // overload #2 int i = f(a); // A -> short, followed by short -> int (rank Promotion) // A -> short, followed by short -> float (rank Conversion) // calls f(int)
L1
is better than list-initialization sequence L2
if L1
initializes an std::initializer_list parameter, while L2
does not.
void f1(int); // #1 void f1(std::initializer_list<long>); // #2 void g1() { f1({42}); } // chooses #2 void f2(std::pair<const char*, const char*>); // #3 void f2(std::initializer_list<std::string>); // #4 void g2() { f2({"foo", "bar"}); } // chooses #4
6) A list-initialization sequence L1 is better than list-initialization sequence L2 if the corresponding parameters are references to arrays, and L1 converts to type "array of N1 T," L2 converts to type "array of N2 T", and N1 is smaller than N2.
|
(since C++11) (until C++20) |
6) A list-initialization sequence L1 is better than list-initialization sequence L2 if the corresponding parameters are references to arrays, and L1 and L2 convert to arrays of same element type, and either
void f(int (&&)[] ); // overload #1 void f(double (&&)[] ); // overload #2 void f(int (&&)[2]); // overload #3 f({1}); // #1: Better than #2 due to conversion, better than #3 due to bounds f({1.0}); // #2: double -> double is better than double -> int f({1.0, 2.0}); // #2: double -> double is better than double -> int f({1, 2}); // #3: -> int[2] is better than -> int[], // and int -> int is better than int -> double |
(since C++20) |
If two conversion sequences are indistinguishable because they have the same rank, the following additional rules apply:
2) Conversion that promotes an enumeration whose underlying type is fixed to its underlying type is better than one that promotes to the promoted underlying type, if the two types are different.
enum num : char { one = '0' }; std::cout << num::one; // '0', not 48 |
(since C++11) |
Mid
is derived (directly or indirectly) from Base
, and Derived
is derived (directly or indirectly) from Mid
Ambiguous conversion sequences are ranked as user-defined conversion sequences because multiple conversion sequences for an argument can exist only if they involve different user-defined conversions:
class B; class A { A (B&);}; // converting constructor class B { operator A (); }; // user-defined conversion function class C { C (B&); }; // converting constructor void f(A) {} // overload #1 void f(C) {} // overload #2 B b; f(b); // B -> A via ctor or B -> A via function (ambiguous conversion) // b -> C via ctor (user-defined conversion) // the conversions for overload #1 and for overload #2 // are indistinguishable; compilation fails
[edit] Implicit conversion sequence in list-initialization
In list initialization, the argument is a braced-init-list, which isn't an expression, so the implicit conversion sequence into the parameter type for the purpose of overload resolution is decided by the following special rules:
- If the parameter type is some aggregate
X
and the initializer list consists of exactly one element of same or derived class (possibly cv-qualified), the implicit conversion sequence is the one required to convert the element to the parameter type. - Otherwise, if the parameter type is a reference to character array and the initializer list has a single element that is an appropriately-typed string literal, the implicit conversion sequence is the identity conversion.
- Otherwise, if the parameter type is std::initializer_list<X>, and there is a non-narrowing implicit conversion from every element of the initializer list to
X
, the implicit conversion sequence for the purpose of overload resolution is the worst conversion necessary. If the braced-init-list is empty, the conversion sequence is the identity conversion.
struct A { A(std::initializer_list<double>); // #1 A(std::initializer_list<complex<double>>); // #2 A(std::initializer_list<std::string>); // #3 }; A a{1.0, 2.0}; // selects #1 (rvalue double -> double: identity conv) void g(A); g({"foo", "bar"}); // selects #3 (lvalue const char[4] -> std::string: user-def conv)
- Otherwise, if the parameter type is "array of N T" (this only happens for references to arrays), the initializer list must have N or less elements, and the worst implicit conversion necessary to convert every element of the list (or the empty pair of braces {} if the list is shorter than N) to
T
is the one used.
|
(since C++20) |
typedef int IA[3]; void h(const IA&); void g(int (&&)[]); h({1, 2, 3}); // int->int identity conversion g({1, 2, 3}); // same as above since C++20
- Otherwise, if the parameter type is a non-aggregate class type
X
, overload resolution picks the constructor C of X to initialize from the argument initializer list
- If C is not an initializer-list constructor and the initializer list has a single element of possibly cv-qualified X, the implicit conversion sequence has Exact Match rank. If the initializer list has a single element of possibly cv-qualified type derived from X, the implicit conversion sequence has Conversion rank. (note the difference from aggregates: aggregates initialize directly from single-element init lists before considering aggregate initialization, non-aggregates consider initializer_list constructors before any other constructors)
- otherwise, the implicit conversion sequence is a user-defined conversion sequence with the second standard conversion sequence an identity conversion.
If multiple constructors are viable but none is better than the others, the implicit conversion sequence is the ambiguous conversion sequence.
struct A { A(std::initializer_list<int>); }; void f(A); struct B { B(int, double); }; void g(B); g({'a', 'b'}); // calls g(B(int, double)), user-defined conversion // g({1.0, 1,0}); // error: double->int is narrowing, not allowed in list-init void f(B); // f({'a', 'b'}); // f(A) and f(B) both user-defined conversions
- Otherwise, if the parameter type is an aggregate which can be initialized from the initializer list according by aggregate initialization, the implicit conversion sequence is a user-defined conversion sequence with the second standard conversion sequence an identity conversion.
struct A { int m1; double m2; }; void f(A); f({'a', 'b'}); // calls f(A(int, double)), user-defined conversion
- Otherwise, if the parameter is a reference, reference initialization rules apply
struct A { int m1; double m2; }; void f(const A&); f({'a', 'b'}); // temporary created, f(A(int, double)) called. User-defined conversion
- Otherwise, if the parameter type is not a class and the initializer list has one element, the implicit conversion sequence is the one required to convert the element to the parameter type
- Otherwise, if the parameter type is not a class type and if the initializer list has no elements, the implicit conversion sequence is the identity conversion.
If the argument is a designated initializer list, a conversion is only possible if the parameter has an aggregate type that can be initialized from that initializer list according to the rules for aggregate initialization, in which case the implicit conversion sequence is a user-defined conversion sequence whose second standard conversion sequence is an identity conversion. If, after overload resolution, the order of declaration of the aggregate's members does not match for the selected overload, the initialization of the parameter will be ill-formed. struct A { int x, y; }; struct B { int y, x; }; void f(A a, int); // #1 void f(B b, ...); // #2 void g(A a); // #3 void g(B b); // #4 void h() { f({.x = 1, .y = 2}, 0); // OK; calls #1 f({.y = 2, .x = 1}, 0); // error: selects #1, initialization of a fails // due to non-matching member order g({.x = 1, .y = 2}); // error: ambiguous between #3 and #4 }
|
(since C++20) |
[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
CWG 1 | C++98 | the behavior was unspecified when the same function with possibly different default arguments (from different scopes) is selected |
the program is ill-formed in this case |
CWG 83 | C++98 | the conversion sequence from a string literal to char* was better than that to const char* even though the former is deprecated |
the rank of the deprecated conversion is lowered (it was removed in C++11) |
CWG 162 | C++98 | it was invalid if the overload set named by F containsa non-static member function in the case of &F(args)
|
only invalid if overload resolution selects a non-static member function in this case |
CWG 280 | C++98 | surrogate call functions were not added to the set of candidate functions for conversion functions declared in inaccessible base classes |
removed the accessibility constraint, the program is ill-formed if a surrogate call function is selected and the corresponding conversion function cannot be called |
CWG 415 | C++98 | when a function template is selected as a candidate, its specializations were instantiated using template argument deduction |
no instantiation will occur in this case, their declarations will be synthesized |
CWG 495 | C++98 | when the implicit conversions for arguments are equally good, a non-template conversion function was always better than a conversion function template, even if the latter may have a better standard conversion sequence |
standard conversion sequences are compared before specialization levels |
CWG 1307 | C++11 | overload resolution based on size of arrays was not specified | a shorter array is better when possible |
CWG 1328 | C++11 | the determination of the candidate functions when binding a reference to a conversion result was not clear |
made clear |
CWG 1374 | C++98 | qualification conversion was checked before reference binding when comparing standard conversion sequences |
reversed |
CWG 1385 | C++11 | a non-explicit user-defined conversion function declared with a ref-qualifier did not have a corresponding surrogate function |
it has a corresponding surrogate function |
CWG 1467 | C++11 | same-type list-initialization of aggregates and arrays was omitted | initialization defined |
CWG 1601 | C++11 | conversion from enum to its underlying type did not prefer the fixed underlying type |
fixed type is preferred to what it promotes to |
CWG 1608 | C++98 | the set of member candidates of a unary operator @ whose argumenthas type T1 was empty if T1 is a class currently being defined
|
the set is the result of qualified name lookup of T1::operator@ in this case
|
CWG 1687 | C++98 | when a built-in candidate is selected by overload resolution, the operands would undergo conversion without restriction |
only convert class type operands, and disabled the second standard conversion sequence |
CWG 2052 | C++98 | ill-formed synthesized function template specializations could be added to the candidate set, making the program ill-formed |
they are not added to the candidate set |
CWG 2076 | C++11 | user-defined conversion is applied to the single initializer in a nested initializer list during list-initialization due to the resolution of CWG issue 1467 |
not applied |
CWG 2137 | C++11 | initializer list constructors lost to copy constructors when list-initializing X from {X} |
non-aggregates consider initializer lists first |
CWG 2273 | C++11 | there was no tiebreaker between inherited and non-inherited constructors |
non-inherited constructor wins |
P2468R2 | C++20 | rewritten candidates based on operator== are added for a != b even if a matching operator!= exists |
not added |
[edit] References
- C++23 standard (ISO/IEC 14882:2023):
- 12.2 Overload resolution [over.match]
- C++20 standard (ISO/IEC 14882:2020):
- 12.4 Overload resolution [over.match]
- C++17 standard (ISO/IEC 14882:2017):
- 16.3 Overload resolution [over.match]
- C++14 standard (ISO/IEC 14882:2014):
- 13.3 Overload resolution [over.match]
- C++11 standard (ISO/IEC 14882:2011):
- 13.3 Overload resolution [over.match]
- C++03 standard (ISO/IEC 14882:2003):
- 13.3 Overload resolution [over.match]